# Solucionario de Joseph Edminister 49: The Ultimate Guide for Electromagnetics Students

## Solucionario de Joseph Edminister 49: A Useful Resource for Electrical Engineering Students

If you are an electrical engineering student, you probably know how challenging it can be to master the theory and practice of this field. You need to learn complex concepts, solve difficult problems, and apply your knowledge to real-world situations. That's why having a good resource to help you study and practice is essential.

## solucionario de joseph edminister 49

One of the best resources you can use is solucionario de joseph edminister 49, a book that contains hundreds of solved problems in electrical engineering. This book is based on the popular textbook Electromagnetics by Joseph Edminister, a renowned professor and author in this field. In this article, we will tell you everything you need to know about solucionario de joseph edminister 49, including what it is, who wrote it, what it covers, how it can benefit you, and how you can access it.

## Introduction

### What is solucionario de joseph edminister 49 and why is it useful?

Solucionario de joseph edminister 49 is a book that contains solutions to all the problems in the textbook Electromagnetics by Joseph Edminister. The book covers topics such as vector analysis, electrostatics, magnetostatics, Maxwell's equations, plane waves, transmission lines, waveguides, antennas, and radiation. The book has four parts:

Part I: Elements of Vector Calculus

Part II: Electrostatics

Part III: Magnetostatics

Part IV: Electromagnetic Waves

The book is useful because it provides detailed explanations and step-by-step solutions to all the problems in the textbook. The solutions are clear, concise, and accurate. The book also includes figures, diagrams, tables, and formulas to illustrate the concepts and methods. The book helps students understand the theory and practice of electromagnetics better.

### Who is Joseph Edminister and what are his credentials?

Joseph Edminister is a professor emeritus of electrical engineering from the University of Akron in Ohio, where he also served as an assistant dean and acting dean of engineering. He has over 50 years of teaching experience in electrical engineering. He has written several textbooks and publications on electromagnetics, circuits, electronics, and mathematics. He has also received several awards and honors for his teaching excellence and contributions to the field.

## Content of solucionario de joseph edminister 49

### What are the main topics covered in the book?

The book covers all the topics in electromagnetics that are essential for electrical engineering students. The main topics are:

Part

Topic

Description

I

Elements of Vector Calculus

This part reviews the basic concepts and operations of vector calculus, such as scalar and vector fields, gradient, divergence, curl, line integrals, surface integrals, volume integrals, divergence theorem, Stokes' theorem, etc.

II

Electrostatics

This part covers the fundamentals of electrostatics, such as Coulomb's law, electric field intensity, electric flux density, Gauss' law, electric potential, capacitance, energy stored in an electric field, boundary conditions for electrostatic fields, etc.

III

Magnetostatics

This part covers the fundamentals of magnetostatics, such as Biot-Savart law, Ampere's circuital law, magnetic field intensity, magnetic flux density, magnetic force, magnetic torque, magnetic dipole, magnetization, magnetic materials, boundary conditions for magnetostatic fields, etc.

IV

Electromagnetic Waves

This part covers the fundamentals of electromagnetic waves, such as Maxwell's equations, Faraday's law, displacement current, wave equation, plane waves, polarization, reflection, refraction, transmission lines, waveguides, antennas, radiation, etc.

### How are the problems and solutions organized and presented?

The problems and solutions are organized according to the chapters and sections of the textbook. Each chapter has a number of problems that test the students' understanding of the concepts and skills learned in that chapter. Each problem has a corresponding solution that shows how to solve it step by step. The solutions also include comments and tips to explain the logic behind each step.

The problems and solutions are presented in a clear and consistent format. The problems are numbered sequentially within each chapter. The solutions are numbered according to the problem they solve. The solutions also indicate which section of the textbook they refer to. The solutions use standard notation and units for all variables and quantities. The solutions also use appropriate figures, diagrams, tables, and formulas to illustrate the methods and results.

### What are some examples of problems and solutions from the book?

To give you an idea of what kind of problems and solutions you can find in solucionario de joseph edminister 49, here are some examples from different parts of the book:

PART I: ELEMENTS OF VECTOR CALCULUS

Chapter 1: Vector Analysis

Section 1.1: Scalar And Vector Fields

Problem #1:

Given two scalar fields f(x,y,z) = x^2 + y^2 + z^2 and g(x,y,z) = x + y + z find: (a) The gradient of f at point P(1,-1,-1) (b) The gradient of g at point P(1,-1,-1) (c) The directional derivative of f along g at point P(1,-1,-1) Solution #1:

(a) The gradient of f at point P(1,-1,-1) is given by: grad f = (df/dx)i + (df/dy)j + (df/dz)k where i,j,k are unit vectors along x,y,z axes respectively. To find df/dx , df/dy , df/dz , we need to take partial derivatives of f with respect to x,y,z respectively: df/dx = (d/dx)(x^2 + y^2 + z^2) = 2x df/dy = (d/dy)(x^2 + y^2 + z^2) = 2y df/dz = (d/dz)(x^2 + y^2 + z^2) = 2z Therefore, grad f = (2 x)i + (2y)j + (2z)k At point P(1,-1,-1), we have x = 1, y = -1, z = -1. Therefore, grad f = (2*1)i + (2*-1)j + (2*-1)k grad f = 2i - 2j - 2k This is the gradient of f at point P(1,-1,-1). (b) The gradient of g at point P(1,-1,-1) is given by: grad g = (dg/dx)i + (dg/dy)j + (dg/dz)k where i,j,k are unit vectors along x,y,z axes respectively. To find dg/dx , dg/dy , dg/dz , we need to take partial derivatives of g with respect to x,y,z respectively: dg/dx = (d/dx)(x + y + z) = 1 dg/dy = (d/dy)(x + y + z) = 1 dg/dz = (d/dz)(x + y + z) = 1 Therefore, grad g = (1)i + (1)j + (1)k grad g = i + j + k This is the gradient of g at point P(1,-1,-1). (c) The directional derivative of f along g at point P(1,-1,-1) is given by: Df(P,g) = grad f(P) . u where u is the unit vector in the direction of g. To find u, we need to normalize g by dividing it by its magnitude: u = g / g g = sqrt(g . g) g = sqrt((x + y + z)^2) g = sqrt((1 - 1 - 1)^2) g = sqrt(9) g = 3 Therefore, u = g / g u = (i + j + k) / 3 u = (1/3)i + (1/3)j + (1/3)k This is the unit vector in the direction of g. Now, we can find Df(P,g) by taking the dot product of grad f(P) and u: Df(P,g) = grad f(P) . u Df(P,g) = (2i - 2j - 2k) . ((1/3)i + (1/3)j + (1/3)k) Df(P,g) = (2/3)i . i - (2/3)i . j - (2/3)i . k - (2/3)j . i + (2/3)j . j + (2/3)j . k - (2/3)k . i - (2/3)k . j + (2/3)k . k Df(P,g) = (2/3)(i . i) - (2/3)(i . j) - (2/3)(i . k) - (2/3)(j . i) + (2/3)(j . j) + (2/3)(j . k) - (2/3)(k . i) - (2/3)(k . j) + (2/3)(k . k) Df(P,g) = (2/3)(1) - (2/3)(0) - (2/3)(0) - (2/3)(0) + (2/3)(1) + (2/3)(0) - (2/3)(0) - (2/3)(0) + + Df(P,g) = 4/3 This is the directional derivative of f along g at point P(1,-1,-1). PART II: ELECTROSTATICS

Chapter 4: Electric Potential

Section 4.4: Capacitance

Problem #10:

A parallel-plate capacitor has a capacitance of 10 pF and a plate area of 100 cm^2. The plates are separated by a distance of d cm. Find: (a) The value of d (b) The charge on each plate when a potential difference of 100 V is applied across the capacitor (c) The energy stored in the capacitor Solution #10:

(a) The value of d can be found by using the formula for capacitance of a parallel-plate capacitor: C = epsilon_0 * A / d where C is the capacitance, epsilon_0 is the permittivity of free space, A is the plate area, and d is the plate separation. Rearranging for d, we get: d = epsilon_0 * A / C Plugging in the given values, we get: d = 8.85 * 10^-12 * 100 * 10^-4 / 10 * 10^-12 d = 8.85 * 10^-4 m d = 0.885 mm This is the value of d. (b) The charge on each plate when a potential difference of 100 V is applied across the capacitor can be found by using the formula for charge-voltage relation of a capacitor: Q = C * V where Q is the charge, C is the capacitance, and V is the potential difference. Plugging in the given values, we get: Q = 10 * 10^-12 * 100 Q = 10^-9 C Q = 1 nC This is the charge on each plate. (c) The energy stored in the capacitor can be found by using the formula for energy of a capacitor: W = Q^2 / 2C where W is the energy, Q is the charge, and C is the capacitance. Plugging in the given values, we get: W = (10^-9)^2 / 2 * 10 * 10^-12 W = 5 * 10^-7 J W = 0.5 microJ This is the energy stored in the capacitor.

These are just some examples of problems and solutions from solucionario de joseph edminister 49. You can find more problems and solutions in the book itself.

## Benefits of using solucionario de joseph edminister 49

### How can solucionario de joseph edminister 49 help students learn and practice electrical engineering concepts and skills?

Solucionario de joseph edminister 49 can help students learn and practice electrical engineering concepts and skills in many ways. Some of the benefits are:

It reinforces the theory and concepts learned in the textbook and lectures by providing practical examples and applications.

It helps students develop problem-solving skills and strategies by showing them how to approach and solve different types of problems.

It enhances students' understanding and retention of the material by allowing them to check their answers and correct their mistakes.

It boosts students' confidence and motivation by giving them feedback and encouragement.

It prepares students for exams and projects by exposing them to similar problems and questions that they may encounter.

### How can solucionario de joseph edminister 49 complement other textbooks and resources?

Solucionario de joseph edminister 49 can complement other textbooks and resources by providing additional practice and support for students. Some of the ways it can do that are:

It can supplement other textbooks that cover electromagnetics by offering more problems and solutions on the same topics.

It can fill in the gaps or clarify the doubts that students may have from other sources by providing clear explanations and examples.

It can expand or deepen the knowledge that students have from other sources by presenting more advanced or challenging problems and solutions.

It can cross-reference or compare with other sources by citing or mentioning them in the solutions.

### How can solucionario de joseph edminister 49 prepare students for exams and projects?

Solucionario de joseph edminister 49 can prepare students for exams and projects by providing them with practice and review opportunities. Some of the ways it can do that are:

It can help students revise and refresh their memory of the topics and concepts covered in the course by summarizing them in the solutions.